mimin

Syntax

mimin(X, window, [minPeriods])

Please see mFunctions for the parameters and windowing logic.

Details

Return the position of the element with the smallest value in X in a sliding window. If there are multiple elements with the identical smallest value in a window, return the position of the first element from the left. Same as other aggregate functions, NULL values are ignored.

Examples

x = 1.2 2 NULL 6 -1 -1
mimin(x, 3);
// output: [,,0,0,2,1]

mimin(x, 3, 1);
// output: [0,0,0,0,2,1]

m=matrix(1 6 2 9 10 3, 9 10 2 6 6 6);
m;

#0	#1
1	9
6	10
2	2
9	6
10	6
3	6

mimin(m,3);

#0	#1


0	2
1	1
0	0
2	0

T = [2022.01.01, 2022.01.02, 2022.01.03, 2022.01.06, 2022.01.07, 2022.01.08, 2022.01.10, 2022.01.11]
X = 1..8
X1 = indexedSeries(T, X)
mimin(X1,3)

	#0
2022.01.01	0
2022.01.02	0
2022.01.03	0
2022.01.06	0
2022.01.07	0
2022.01.08	0
2022.01.10	0
2022.01.11	0

t= 2021.01.02 2021.01.05  2021.01.06  2021.01.09 2021.01.10 2021.01.12
m=matrix(5 4 NULL -1 2 4, 3 2 8 1 0 5)
m1=m.rename!(t, `a`b).setIndexedMatrix!()
mimin(m1,3)

	a	b
2021.01.02	0	0
2021.01.05	0	0
2021.01.06	0	0
2021.01.09	0	0
2021.01.10	0	1
2021.01.12	0	0

Related functions: imin, mimax