mimax

Syntax

mimax(X, window, [minPeriods])

Please see mFunctions for the parameters and windowing logic.

Details

Return the position of the element with the largest value in X in a sliding window. If there are multiple elements with the identical largest value in a window, return the position of the first element from the left. Same as other aggregate functions, NULL values are ignored.

Examples

x = 1.2 2 NULL 6 -1 6
mimax(x, 3);
// output: [,,1,2,1,0]

mimax(x, 3, 1);
// output: [0,1,1,2,1,0]
m=matrix(1 6 2 9 10 3, 9 10 2 6 6 6);
m;
#0 #1
1 9
6 10
2 2
9 6
10 6
3 6 
mimax(m,3);
#0 #1

1 1
2 0
2 1
1 0 
T = [2022.01.01, 2022.01.02, 2022.01.03, 2022.01.06, 2022.01.07, 2022.01.08, 2022.01.10, 2022.01.11]
X = 1..8
X1 = indexedSeries(T, X)
mimax(X1,3)
#0
2022.01.01 0
2022.01.02 1
2022.01.03 2
2022.01.06 0
2022.01.07 1
2022.01.08 2
2022.01.10 1
2022.01.11 1 
t= 2021.01.02 2021.01.05  2021.01.06  2021.01.09 2021.01.10 2021.01.12
m=matrix(5 4 NULL -1 2 4, 3 2 8 1 0 5)
m1=m.rename!(t, `a`b).setIndexedMatrix!()
mimax(m1,3)
a b
2021.01.02 0 0
2021.01.05 0 0
2021.01.06 0 1
2021.01.09 0 0
2021.01.10 1 0
2021.01.12 1 1

Related functions: imax, mimin